Free energy

Extragerea energiei din mediul inconjurator nu e o utopie si stiinta oficiala foloseste acest lucru.Astfel aparatul meu de aer conditionat pe care il folosesc toamna si primavara la incalzit consuma 700 w si da caldura in camera de 2500 w.

virgil a scris:
Cum ai masurat acest lucru?

Scrie clar in datele tehnice.Putere consumata la incalzire(cit consuma din retea) si COP (W/W) aproximativ 3.5 de cite ori e mai mare puterea reala de incalzire decat consumul.

george a scris: Cum ar trebui sa arate o sursa de energie ideala?
Radiatia solara e principala sursa de energie a planetei.Dezavantajul ei e ca intensitatea ei nu e constanta.La fel se intampla si cu energia eoliana.Nici in cazul caderilor de apa nu avem todeauna debit constant.
Putem gasi o sursa energetica cu un nivel constant al intensitatii si sa fie omniprezenta?
Energia interna[u] a aerului! Avem permanent 250 000 J pe m^3.
Mi se pare ,cel putin,curios ca nu se acorda prea mare atentie acestei surse.

gafiteanu a scris:Sau desfaci cu grija aparatul si furi ideea. E aproape gratis.

Oare cu cat vinde OZNul escrocul?

george a scris:Energia interna pentru aer la diferite temperaturi,exprimata in KJ/Kmol:
Sursa: Termodinamica tehnica C.A. Vasilescu
-250=5181,5 ;300=6218,9 ;350=7264,9 ;400=8316,3 ;500=10448,4 . pag.340.
-masa kilomolului (kg/kmol)=28,966.
-masa specifica (kg/Nm^3)=1,293. Pag.328.
In conditii normale de presiune (pN=760 mm Hg) si temperatura (273,15K) un Kmol de aer are 22,4 M^3.
Dependenta dintre parametrii de stare intr-o transformare izobara sunt:
V1/V2=T1/T2
In consecinta daca in conditii normale avem V=22,4,pentru pN vom avea la :
-250K => V=20,5 ;300K =>V=24,6 ; 350K =>V=28,7 ; 400K =>V=32,8 ; 500K => V=41
Acum,pentru un m^3 de aer in conditii de pN avem:
-la 250K 5181500/20,5=252756 J
-la 300K 6218900/24,6=252800 J
-la 350K 7264900/28,7=253132 J
-la 400K 8316300/32,8=253545 J
-la 500K 10448400/41=254839 J

Razvan a scris: Prices
3-4 KW AC/DC units : € 5 000
10 KW AC/DC units : € 20 000
Păi cu banii ăştia plătesc curentul electric j'de ani de acum înainte şi-mi mai şi rămâne!

gafiteanu a scris:1)-Nu e nucleara, se scrie asa la deruta.

Vor veni si chinezii cu minunea. .

Razvan a scris: ]De fapt, Keshe nici nu precizează la ce perioadă se referă cei 3 - 4 kw.

CAdi a scris: Gafiteanu, nu vezi ca cineva incearca sa ne puna ?

sadang a scris:Razvane incepe de aici:

Another interesting aspect of this levitation demonstration is the small amount of power necessary to perform the levitation. The loudest tolerable sound pressure that a person can stand is approximately 280 dynes/cm2. From physics analysis this translates to about 0.000094 watts/cm2.

If we assume that each monk with his instrument produced one half this much sound energy (which is highly unlikely) and we make the further gross assumption that this is the amount if power that reaches the stone (actually sound dissipates rapidly over distance), we would have about 0.04 watts (i.e., (19 instruments + 19 x 4 monks) x 0.000094) hitting the huge stone block.

This is an astoundingly small amount of energy actually hitting the 1.5 cubic meter stone to produce the effect.

To lift the stone 250 meters takes a prodigious amount of energy. Rocks such as granite and limestone have weights in the neighborhood of 150-175 pounds per cubic foot.

If we assume a nominal value of 160 pounds per cubic foot then the 1.5 cubic meter stones weighed around 8475 pounds (i.e., over 4 tons!!!). To lift the 8475 pounds 250 meters would require about 7 million ft-pounds of work (i.e., 8475 pounds X 250 meters / 0.30408 meters/foot = 6,968,035).

Since this was done over a 3 minute period then about 70 horsepower was produced (i.e., 7 x 106 foot-pounds / 180 seconds / 550 horsepower/foot-pound/second = 70.384). This is equivalent to 52 kilowatts (i.e., 70.384 X 0.74570 kilowatts/horsepower = 52.5).

The over unity power factor we obtain is 5,250,000 over unity (i.e., 52,500 watts/0.01 watts).

The monks were obviously tapping into a huge amount of free energy to levitate the huge stone blocks, or gravity requires little power to affect its operation once the principles are understood.

Razvan a scris:Am citit suficient despre prostiile ăluia, ca să-mi dau seama că nu merită să-mi mai bat capul!